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2. Electric Potential and Capacitance
medium
$Q$ વિઘુતભારથી એક બિંદુ આગળનું વિદ્યુતસ્થિતિમાન $V=Q$$ \times {10^{11}}\,V$ છે.આ બિંદુ એ વિદ્યુતક્ષેત્રની તીવ્રતા _______
A
$4\pi {\varepsilon _0}Q \times 10^{20}\;V/m$
B
$\;12\pi {\varepsilon _0}Q \times {10^{22}}\;V/m $
C
$\;4\pi {\varepsilon _0}Q \times {10^{22}}\;V/m$
D
$\;12\pi {\varepsilon _0}Q \times {10^{20}}\;V/m $
(AIPMT-2008)
Solution
$V =\frac{1}{4 \pi \varepsilon_{0}} \cdot \frac{Q}{r}=Q \cdot 10^{11} \text { volts }$
$\therefore \frac{1}{r} =4 \pi \varepsilon_{0} \cdot 10^{11}$
$E =\frac{\text { potential }}{r}=Q \cdot 10^{11} \times 4 \pi \varepsilon_{0} \cdot 10^{11}$
$\Rightarrow E=4 \pi \varepsilon_{0} \cdot Q \cdot 10^{22} \,\mathrm\,{volt/m}$
Standard 12
Physics
